BST — Beam Solver Tool ← Slabs binder

The BST binders · Slabs binder · From the slab to the beam · updated 27.9.2026

Beam dimensionsDepth in a solid slab, width in a ribbed slab

Same idea as the slab thickness — with the beam: hreq = L0 / (K11 · K12 · K13)

  • Solid Looking for the depth: K12 = 5.25 · ∛(b / fser), K11 = 1 (rectangular section)
  • Ribbed The beam is hidden — depth = slab thickness. Looking for the width: K12 = L0 / (K11 · h · K13) → b = fser · (K12 / 5.25)³ — the same formula, just inverted

fser of a beam in a solid slab = q from the load transfer + its self-weight. In a hidden beam — only q from the load transfer. The governing segment: the largest L0 · ∛fser.

  1. 01

    Why a 'governing segment'? (30 seconds)

    • A continuous beam crosses several spans — and each span has its own length and load.
    • Deflection grows with length and with load → compare L0 · ∛fser of every segment, and the largest governs.
    • Not always the longest span: a short span with a heavy load can win.
  2. 02

    Solid slab: a beam 30 wide — what is the depth?

    A beam on 3 supports (3.4 + 4.6 m), width b = 30. A slab rests on the 4.6 segment: q = 2.3 t/m; on the 3.4 segment — none.

    • L0
      0.8 · 340 = 272 · 0.8 · 460 = 368 cm
    • h₀
      368 / 10 = 36.8 → round up in steps of 5, minimum 30 → h0 = 40 cm
    • S.w
      2.5 · (40/100) · (30/100) = 0.3 t/m
    • fser
      0 + 0.3 = 0.3 · 2.3 + 0.3 = 2.6 t/m
    • Governing segment
      272 · ∛0.3 = 182.09 · 368 · ∛2.6 = 506.03 → the 4.6 segment
    • K12
      5.25 · ∛(30 / 2.6) = 11.86
    • Required h
      368 / (1 · 11.86 · 1) = 31.03 → 32 ≤ 40 passes ✓

    That's it. Beam 30/40.

    And if the exercise gives h = 30 ('check')? S.w = 0.225 → fser = 2.525 → K12 = 11.98 → hreq = 30.72 → 31 > 30 — does not pass. In a 'check' question this is the answer; in a 'design' question — increase in steps of 5 cm above the required h and calculate again.

    Units: b and h in cm, fser of a beam in t/m.

  3. 03

    Ribbed slab: hidden beam — looking for the width

    In a ribbed slab the beam is 'swallowed' by the slab thickness: h = 33 cm is given. In the governing segment q = 6.403 t/m, L0 = 413 cm. In a hidden beam fser is only the q from the load transfer.

    • Beam depth = slab thicknessh = 33 cm
    • Load coefficientK12 = L0K11 · h · K13 = 4131 · 33 · 1 = 12.52
    • Required widthbreq = fser · (K125.25)³ = 6.403 · (12.525.25)³ = 86.84 cm
    • Beam width (steps of 5 cm)breq = 86.84 → b = 90 cm ✓

    That's it. A hidden beam 90 cm wide — wide, but it does not protrude from the slab.

  4. 04

    4 pitfalls

    • Forgetting the beam's self-weight. In a solid slab fser of the beam = q + S.w; only in a hidden beam — q alone.
    • The governing segment = the longest. Compare products, not lengths.
    • Hidden-beam width in whole cm. Round up to steps of 5 cm.
    • Calculating depth in a ribbed slab. The depth is already given — the slab thickness.

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Slabs binder · BST · beamsolvertool.com/en/learn/slabs/beam-size/

Solve a slab in BST BST finds the governing segment and calculates the beam depth or width

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